High-efficiency buck Ubec module | 5V/3A output | Essential power converter for RC aircraft/drone

Specifications:
Output: 5V/3A
Input: 5.5V-26V (2-6 cells Lipo pack or 5-18 cells NiMH pack)
Ripple:
Demension: 26 x 12 x 11mm/ 1.02" x 0.47" x 0.43" (Approx.)
Note: This is not an electrical switch, just an independent UBEC, which cannot be connected to a motor

Package includes:
2x FPV UBEC 5V 3A

Product Features:
1. The switching power supply structure is designed, and the frequency of the switching power supply main control chip is 300KHz. It also has overcurrent and overtemperature protection functions, and the chip efficiency is as high as 92%.
2. Small size and light weight.
3. The electronic devices are protected by a shielding cover.
4. It has a protection function to prevent the power supply polarity from being reversed. If the power supply is accidentally reversed, it will not cause damage to the UBEC.
5. It has an LED light-emitting diode working status indicator, which lights up when the output is normal.
6. Advantages compared with traditional BEC: Compared with BEC using switching power supply mode and BEC using linear voltage regulation, the advantages are mainly reflected in: when using more than 3 strings (11.1V) of batteries, it can greatly reduce the heating of BEC and improve the overall efficiency.

***For example: when using 4 strings of lithium batteries, the voltage is about 14.8V during normal use.
---Using the traditional linear voltage regulation method, to output 5V/1A current, the power supply end must also input 1A current. Therefore, 14.8Vx1A=14.8W of power will be consumed by BEC, but the actual useful output of BEC is only 5Vx1A=5W, so the overall efficiency is only 5/14.8=33.8%, and the other 9.8W of power consumption is converted into heat, which will cause BEC to overheat and the chip to enter the protection state and fail to work. Using the switching power supply method, to output 5V/1A current, our actual test shows that the power supply end only needs to input 0.38A of current, that is, 14.8Vx0.38A=5.6W of power, so the overall efficiency is 5/5.6=89.3%